Re: Resource ID# 5 and Resource id #5 8561 errors....help
| From: | Terion Miller | Date: | Fri, 12 Dec 2008 23:17:12 +0000 |
| Subject: | Re: Resource ID# 5 and Resource id #5 8561 errors....help | ||
| References: | 1 2 3 4 5 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-284570@lists.php.net to get a copy of this message | ||
On Fri, Dec 12, 2008 at 5:08 PM, Daniel P. Brown
<daniel.brown@parasane.net>wrote:
> On Fri, Dec 12, 2008 at 18:03, Terion Miller <webdev.terion@gmail.com>
> wrote:
> >
> > Well I did some changes and I must be learning because although I have
> the
> > same error I don't have new ones...
> > so now the code is like this:
> > $sql = "SELECT * FROM
importimages WHERE
> > Category = 'Obits'";
> > $result = mysql_query($sql) or die("Error in
> > ".__FILE__.":".__LINE__."
> > - ".mysql_error());
> > while($object = mysql_fetch_object($result)) {
> > foreach($object as $k => $v) {
> > echo stripslashes($k).": ".stripslashes($v)."<br />\n";
> > }
> > }
> >
> >
> > $FileName = $object->Image; <-------This is the line that is
> telling
> > me it is "trying to get the properties of a non-object....
>
> That's because you're calling that as an object using OOP
> standards, where I gave you procedural code. To interface with my
> code, just call it as:
>
> <?php
> // .... other code here....
> while($row = mysql_fetch_array($result)) {
> echo $row['Image']."<br />\n"; // If
> Image is the column name.
> }
> // .... code continues....
> ?>
>
> --
> </Daniel P. Brown>
> http://www.parasane.net/
> daniel.brown@parasane.net || danbrown@php.net
> 50% Off Hosting! http://www.pilotpig.net/specials.php
>
Here is the full chunk:
$sql = "SELECT * FROM importimages WHERE Category =
'Obits'";
$result = mysql_query($sql) or die("Error in ".__FILE__.":".__LINE__."
- ".mysql_error());
while($object = mysql_fetch_object($result)) {
foreach($object as $k => $v) {
echo stripslashes($k).": ".stripslashes($v)."<br />\n";
}
}
$FilePath = "output/WebImagesHiRes/";
$BackupPath = "output/WebImagesHiRes/backup/";
$FileName = $object->Image; //<----because it is going to process an
image doesnt that make it oop?
$FileName = str_replace("/", "", $FileName);
$FileName = str_replace(".jpg", "", $FileName);
Well its late friday afternoon here, I'm ready to break away from my
desk...maybe on monday I will be able to get it working (right now our obit
pics in the online paper are not getting posted...oops)
Thanks folks
yawn LEts call it a weekend woooot
terion