RE:Please Help me!!!

From: Date: Mon, 04 Dec 2000 06:49:56 +0000
Subject: RE:Please Help me!!!
References: 1  Groups: php.general 
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Hi, I have some problem with my SQL queries. Maybe this problem is quite easy for you all but I'm still not familiar with PHP so I hope you all can help me. I need it quite urgently to solve my company program. I am writing PHP3 with MYSQL. I need to query multiple data from one table to compare them with other table. For example I need to select data a,b,c,d from table 1 and then compare with data in table 2. If these data are matching with table 2, then I don't want to display them. I only want to display the one which are not match. here is my error coding: $count=0; $query1 ="select doc from table1 where doc_no='$x' and doc_rev='$y' and status='$o' and title_type='$b' "; $result1 = mysql_query($query1,$db); while($doc = mysql_fetch_row($result1)) { $query = "select $a,$b,$c,$d from table 2 where status=$o and a !='$doc[0]' order $b"; $result1 = mysql_query($query,$db); while($data = mysql_fetch_row($result1)) { print "data=$data[0]<br>\n"; } $count++; } Can you help me to correct them? I can't make only unmatched data to display on the form because they are while looping. so please help me. thanks a lot. from Wendy

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