Re: print a to z

2009/1/15 Leon du Plessis <leon@dsgnit.com>: > I used that notation before, and it did not work 100%. > Adapt as follows: > > for ($i = 'a'; $i <= 'z'; $i++) > if ($i == "aa") break; else echo $i; It's weird, but true--the simple '<=' breaks the loop. However, in the above example, you don't need the 'else'; the 'break' ensures that the 'echo $i'; will not execute. You can step around the the problem more elegantly: for ($i = 'a'; $i !== 'aa'; $i++) { echo $i; } Regards, Torben > -----Original Message----- > From: Paul M Foster [mailto:paulf@quillandmouse.com] > Sent: 16 January 2009 07:55 AM > To: php-general@lists.php.net > Subject: Re: [PHP] print a to z > > On Thu, Jan 15, 2009 at 08:32:14PM -0800, paragasu wrote: > >> i have this cute little problem. i want to print a to z for site > navigation >> my first attempt work fine >> >> for($i = '65'; $i < '91'; ++$i) >> echo chr($i); >> >> but someone point me a more interesting solutions >> >> for($i = 'a'; $i < 'z'; ++$i) >> echo $i >> >> the only problem with the 2nd solutions is it only print up to Y without > z. >> so how to print up to z with the 2nd solutions? because it turn out >> that you cant to something >> like for($i = 'a'; $i <= 'z'; ++$i).. > > for ($i = 'a'; $i <= 'z'; $i++) > echo $i; > > Paul > > -- > Paul M. Foster