Re: Making a Variable from different tables with Matching Dbfields?

> > > Your post made perfect sense to me about the INNER JOIN , I looked it up >> but it is not returning the AdminID, maybe my syntax is wrong? >> >> $query = "SELECT admin.AdminID , workorders.AdminID >> FROM admin >> INNER JOIN >> workorders >> ON AdminID(admin, workorders) >> WHERE admin.UserName = '".$_SESSION['user']."' >> "; >> > > The syntax is wrong. > > inner join workorders using (adminid) > ^^ > only works if both tables are using the same field name, the db will expand > it into the syntax below. Here you just need to specify the fieldname to > join on (ie the common one). > > or > > inner join workorders on (admin.adminID=workorders.adminID) > ^^ > if the field names are not named the same, eg: > > select * from > comments > inner join users on (comments.user_id=users.id) > > Well I tried both ways and still cannot get it to pick up the AdminID, $query"SELECT admin.AdminID , workorders.AdminID FROM admin INNER JOIN workorders on AdminID WHERE admin.UserName = 'tmiller' "$result""$row"" $SortBy"WorkOrderID DESC"$Page"1"$PerPage"30"$StartPage"0"$sql"SELECT admin.AdminID , workorders.AdminID FROM admin INNER JOIN workorders ON AdminID(admin, workorders) WHERE admin.UserName = 'tmiller' "$Total"0"