Re: Re: Problems with displaying results

On Tue, Mar 3, 2009 at 10:32 AM, Shawn McKenzie <nospam@mckenzies.net>wrote: > Terion Miller wrote: > > I have two queries one pulls out which users to use and the second pulls > > those users orders.... > > Looks something like this but is only pulling the first record: > > > > > > $query = "SELECT UserName, > > AdminID FROM admin > > WHERE Key1 = 'YES' "; > > > > $result = mysql_query ($query) ; > > $row = mysql_fetch_assoc($result); > > > > //Reveal Variables for Debugging > > // include("VariableReveal2.php"); > > echo ("Hello <br>"); > > //echo $row['AdminID']; > > echo ($row['UserName']); > > > > > > > > > > if ($row['Key1'] == "NO") { > > header ("Location: Welcome.php?AdminID=$AdminID&msg=Sorry, you do > > not have access to that page."); > > } > > > > if (isset($_GET['SortBy'])) {$SortBy = $_GET['SortBy'];} else {$SortBy > > = > > 'WorkOrderID DESC';} > > if (isset($_GET['Page'])) {$Page = $_GET['Page'];} else {$Page = 1;} > > > > $PerPage = 30; > > $StartPage = ($Page - 1) * $PerPage; > > > > second query here is using the $row from the first (and yes I > know > > not to use *, just did so here to keep post shorter) > > > > $sql= "SELECT * FROM workorders WHERE AdminID = > > '".$row['AdminID']."' "; > > // $sql .= "ORDER BY $SortBy LIMIT $StartPage, $PerPage"; > > $result = mysql_query ($sql); > > $row2 = mysql_fetch_assoc($result); > > $Total = ceil(mysql_num_rows($result)/$PerPage); > > > > > > So this works but only half way as it only displays the first record > in > > the table. > > > > > > > > > > Thanks > > Terion > > > > Happy Freecycling > > Free the List !! > > www.freecycle.org > > Over Moderation of Freecycle List Prevents Post Timeliness. > > ------------------------------------------------ > > Twitter? > > http://twitter.com/terionmiller > > ------------------------------------------------ > > Facebook: > > <a > > href="http://www.facebook.com/people/Terion-Miller/1542024891" > > title="Terion Miller's Facebook profile" target=_TOP><img src=" > > > > http://badge.facebook.com/badge/1542024891.237.919247960.png" > > border=0 > > alt="Terion Miller's Facebook profile"></a> > > Groucho Marx - "I have had a perfectly wonderful evening, but this > wasn't > > it." > > > > You need to lookup the mysql_fetch_assoc() function. It only returns > one row from a result set that may contain multiple rows. You need > something like: > > while($row = mysql_fetch_assoc($result)) { > // do something with $row > } > > --------------------------------------------------- well I looked it up in my book and tried this example but still get the same thing, the first record $result = mysql_query ($query) ; //$row = mysql_fetch_array($result); while ($row = mysql_fetch_row($result)){ for ($i=0; $i<mysql_num_fields($result); $i++) echo $row[$i] . " "; //print a return for neatness sake echo "\n";