if elseif elseif elseif....
| From: | PJ | Date: | Wed, 04 Mar 2009 22:51:11 +0000 |
| Subject: | if elseif elseif elseif.... | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-289294@lists.php.net to get a copy of this message | ||
This is probably a mysql question, but their list is rather dull - I
think they don't appreciate my humor. Beside this list is fun ... and
informative.
Anyway, I can't figure this out. I am trying to verify inputs on a form
and even if I have all the required fields right, I still get the error
that there are empty obligatory fields.
This is what I am using... but I'm open to anything that works or is
more efficient:
if (strlen($_POST["titleIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["first_nameIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["publisherIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["copyrightIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["ISBNIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["languageIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif (strlen($_POST["categoriesIN"]) == 0 ) {
$obligatoryFieldNotPresent = 1;
}
elseif ($obligatoryFieldNotPresent = 1) {
$obligatoryFieldNotPresent = 0;
}
I've tried closing with
else ($obligatoryFiieldNot Present = 0);
end;
but that give me a blank page - haven't figure out how to check for
parsing or scripting errors
Thanks for any suggestions.
--
unheralded genius: "A clean desk is the sign of a dull mind. "
-------------------------------------------------------------
Phil Jourdan --- pj@ptahhotep.com
http://www.ptahhotep.com
http://www.chiccantine.com/andypantry.php