Re: DATE / strtotime

Ron Piggott wrote:

Where $date_reference is 2009-04-18 the following code gives me a day of 1969-12-30. How do I get it to be 2009-04-17? $previous_date = strtotime("-1 days", $date_reference); $previous_date = date('Y-m-d', $previous_date); echo $previous_date; outputs 1969-12-30 Ron

You need to read the strtotime page in the manual. http://php.net/strtotime It says that the second argument of the strtotime function is suppose to be a unix time stamp. Is the value that you gave us for $date_reference a unix time stamp? No Your code should be like this. // This converts 2009-04-19 00:00:00 into 1240099200 $date_reference_unix = strtotime($date_reference); $previous_date = strtotime("-1 days", $date_reference_unix); $previous_date = date('Y-m-d', $previous_date); echo $previous_date; outputs 1969-12-30 -- Jim Lucas "Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them." Twelfth Night, Act II, Scene V by William Shakespeare