Re: Re: unzip a file - destination folder wrong

<snip> > >> >> $fp = fopen(dirname($filename) . '/' . zip_entry_name($zip_entry), >> "w"); >> >> > thank you this worked. How come the . '/' . zip_entry_name($zip_entry) is > needed? Looks like a double file name, but the result is ok. Could you > explain this line? </snip> read carefully, you'll understand too. :) its extracting the directory name with the dirname($filename) then concatenation with the name of zip file only :) regards Lenin www.twitter.com/nine_L