Re: populate form input option dropdown box from existing data

Stuart wrote: > 2009/6/18 PJ <af.gourmet@videotron.ca>: > >> Martin Scotta wrote: >> >>> It is a sintax error >>> >>> if (in_array($ex, $selected) <--- missing ) >>> echo "<br />yes"; >>> else echo "<br />no"; >>> >>> On Thu, Jun 18, 2009 at 10:13 AM, PJ <af.gourmet@videotron.ca >>> <mailto:af.gourmet@videotron.ca>> wrote: >>> >>> Ford, Mike wrote: >>> > On 17 June 2009 14:30, PJ advised: >>> > >>> > >>> > >>> >> For the moment, I am trying to resolve the problem of >>> >> extracting a value >>> >> from a string returned by a query. I thought that in_array() >>> would do >>> >> it, but the tests I have run on it are 100% negative. The only >>> thing I >>> >> have not used in the tests is third parameter bool $strict >>> which only >>> >> affects case-sensitivity if the $needle is a string. >>> >> >>> > >>> > $strict has nothing whatsoever at all in any way to do with case >>> > sensitivity -- $strict controls whether the values are compared >>> using >>> > equality (==) or identity (===) tests. As is stated quite >>> clearly on the >>> > manual page, in_array() is always case-sensitive. >>> > >>> > >>> >> This leads me to >>> >> believe that in_array() is either inappropriately defined in >>> >> the manual >>> >> and not effective on associative arrays >>> >> >>> > >>> > Complete rubbish -- the in_array() manual page is excellent and >>> totally >>> > accurate, complete with 3 working examples. >>> > >>> > >>> I would really like to understand why my attempts to reproduce the >>> first >>> example just did not work. >>> Note also that the examples do not show in_array($string, $array) >>> My array was Array ([0]=>6[1]=>14....), so when I tried if >>> (in_array($string, $array) , echo $string did not return 14 as I had >>> expected; neither did if(in_array("14", $array) ... nor >>> if(in_array(14, >>> $array). It still does not... actually, the screen goes blank. >>> So, what am I doing wrong? >>> Here's what is not working... I'm trying to reproduce the example from >>> php.net <http://php.net>: >>> >>> $selected = array(); >>> if ( ( $results = mysql_query($sql, $db) ) ) { >>> while ( $row = mysql_fetch_assoc($results) ) { >>> $selected[] = $row['id']; >>> } >>> } >>> print_r($selected); >>> $ex = 14; >>> if (in_array($ex, $selected) >>> echo "<br />yes"; >>> else echo "<br />no"; >>> >>> Regardless if I put 14 into $ex or "14" or '14' or even if I >>> put >>> the 14 >>> instead of the $ex into the if line, I get a blank screen. It seems tp >>> me, from what I see in the manual that this should work... or am I >>> supposed to know something that is not clear in the examples... ? >>> >>> >>> -- >>> Hervé Kempf: "Pour sauver la planète, sortez du capitalisme." >>> ------------------------------------------------------------- >>> Phil Jourdan --- pj@ptahhotep.com >>> <mailto:pj@ptahhotep.com> >>> http://www.ptahhotep.com >>> http://www.chiccantine.com/andypantry.php >>> >>> >>> -- >>> PHP General Mailing List (http://www.php.net/) >>> To unsubscribe, visit: http://www.php.net/unsub.php >>> >>> >>> >>> >>> -- >>> Martin Scotta >>> >> Actually, we have to call it a typo because i fixed that and the results >> are exactly the same = blank screen. :-( >> > > If you're getting a blank screen instead of an error message I highly > recommend turning display_errors on and setting error_reporting to > E_ALL in you dev php.ini - that way you'll actually see error messages > rather than having to hunt through the code by hand. > Duh, Stuart, I'm wet behind the ears, but that was one of my first revelations - to use error_reporting(E_ALL); ini_set('display_errors', 1); ;-) But that's what's weird... if I comment those last 4 lines out, the proggie works (or shall I say, limps; I still have other problems) But the in_array just refuses to cooperate. -- Hervé Kempf: "Pour sauver la planète, sortez du capitalisme." ------------------------------------------------------------- Phil Jourdan --- pj@ptahhotep.com http://www.ptahhotep.com http://www.chiccantine.com/andypantry.php