Re: why is this shell_exec() failing to execute my shell to create a symlink?

Make sure that: - The user executing the script (apache I presume) has execute permissions on ls and ln binaries. - The user executing the script has write persmissions on the directory you are trying to write, and read permissions where you do ls. - This will probably help: put the full binary path for ls and ln, it depends on your OS, but probably they are: /bin/ls and /bin/ln If that doesn't help, can you show us the output? Jonathan On Sat, Jun 27, 2009 at 5:46 PM, Govinda<govinda.webdnatalk@gmail.com> wrote: > this code: > > <?php > >        $testOutput = shell_exec("ls"); > >        $where2cd2='testDir/'; >        $firstCMD="cd $where2cd2"; >         $firstOutput = shell_exec("$firstCMD"); >        // $firstOutput = shell_exec('cd testDir/'); >        $testOutput2 = shell_exec("ls"); > >        $secondCMD='ln -s amex_cid.gif myccGOV.gif'; >        $secondOutput = shell_exec("$secondCMD"); > >        echo "testOutput:<br><pre>$testOutput</pre>"; >        echo > > "testOutput2:<br><pre>$testOutput2</pre><br>firstCMD=$firstCMD<hr>"; >        echo > > "firstOutput:<br><pre>$firstOutput</pre><br>secondCMD=$secondCMD<hr>"; >        echo > > "secondOutput:<br><pre>$secondOutput</pre><br>thirdCMD=$thirdCMD<hr>"; > > ?> > > is not producing the symlink that I think it should.  (?!?)  (neither in the > dir/ where this script lives, nor in the testDir/ where I am actually trying > to create it, on the fly. > Server is not in safe mode. > > > ------------ > Govinda > govinda.webdnatalk@gmail.com > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >