Re: Call to object function, want to PHP interpret returned string

John Allsopp wrote: > Hi > > At the top of a webpage I have: > > <?php > include_once("furniture.php"); > $myFurniture = new furniture(); > echo $myFurniture->getTop("my company title"); > ?> > > to deliver the first lines of HTML, everything in HEAD and the first > bits of page furniture (menu, etc). > > In the furniture object in getTop(), I want to return a string that > includes the CSS file that I call with an include_once. But the > include_once isn't interpreted by PHP, it's just outputted. So from: > > $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 > Transitional//EN' ........ > <?php > include_once('styles3.txt'); > ?> > ......."; > > return $toReturn; > > I get > > <?php > include_once('styles3.txt'); > ?> > > in my code. > > Do I really have to break up my echo $myFurniture->getTop("my company > title"); call to getTopTop, then include my CSS, then call getTopBottom, > or can I get PHP to interpret that text that came back? > > PS. I may be stupid, this may be obvious .. I don't program PHP every day > > Thanks in advance for your help :-) > > Cheers > J First guess is that your page doing the including doesn't have a filename with a .php extension, and your server is set to only parse php in files with a .php extension. Cheers -- David Robley If you saw a heat wave, would you wave back? Today is Boomtime, the 41st day of Confusion in the YOLD 3175.