Re: [GD] Image errors

He is calling the function by variable something like this $func = 'var_dump'; $func( new Foo ); On Tue, Jul 14, 2009 at 1:30 PM, Ashley Sheridan<ash@ashleysheridan.co.uk> wrote: > On Tue, 2009-07-14 at 13:27 -0300, Martin Scotta wrote: >> $immagine = $tipo($this->updir.$id.'.png'); >> >> $tipo is undefined >> >> >> On Tue, Jul 14, 2009 at 12:48 PM, Il pinguino >> volante<tuxsoul@codeinside.it> wrote: >> > Hi to all >> > >> > I get a problem processing an image with GD libraries. >> > >> > This is my function >> > >> >   public function showPicture($id) { >> >       header('Content-type: image/jpeg'); >> >       $mime = mime_content_type($this->updir.$id.'.png'); >> >       $type = explode('/',$mime); >> >       $type = 'imagecreatefrom'.$type[1]; >> >       $immagine = $tipo($this->updir.$id.'.png'); >> >       imagejpeg($immagine,null,100); >> >       imagedestroy($immagine); >> >   } >> > >> > If i commentize the "header" function i get a lot of strange simbols (such >> > as the code of a jpeg image!) but no errors. >> > The result of this code is a blank page. In Firefox the title sets to >> > "picture.php (JPEG image)" and if i right-click it and click on >> > "Proprieties" i get "0px × 0px (resized as 315px × 19px)". >> > >> > P.S.: I get the same result when I write $immagine = >> > imagecreatefromjpeg(...) >> > >> > (Sorry for my english) >> > >> > Thanks in advance, >> > Alfio. >> > >> > -- >> > PHP General Mailing List (http://www.php.net/) >> > To unsubscribe, visit: http://www.php.net/unsub.php >> > >> > >> >> >> >> -- >> Martin Scotta >> > Also, it doesn't look like you're actually doing anything with $type > > Thanks > Ash > www.ashleysheridan.co.uk > > -- Martin Scotta