Re: PHP/mysql equivalent of PEAR's tableInfo()??
| From: | Jason Pruim | Date: | Thu, 16 Jul 2009 03:03:09 +0000 |
| Subject: | Re: PHP/mysql equivalent of PEAR's tableInfo()?? | ||
| References: | 1 2 3 4 5 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-295447@lists.php.net to get a copy of this message | ||
On Jul 13, 2009, at 10:03 AM, Govinda wrote:
Better late then never! :) I played around with your code tonight and got this working on a test server: <?PHP $db_billing = mysql_connect($DBHOST, $DBUSER, $DBPASS) or die("Could not connect: " .mysql_error()); $db_selected = mysql_select_db($DB, $db_billing);I have this code:Yes. 3 lashing. Thanks. I am not likely to neglect again remembering that mysql and mysqli are different and have different syntax. unfortunately I am still in over my head enough to have to ask.. Here is what I have now: $db_billing=mysql_connect(localhost,metheuser,mypass,billing); if (!$db_billing) { die('Could not connect: ' . mysql_error()); } $sql = "SHOW TABLES"; $result = mysql_query($sql); foreach(mysql_fetch_assoc($result) as $k => $v) { //line 62 $ssql = "DESCRIBE ".mysql_real_escape_string($v); $rresult = mysql_query($ssql); echo "<b>".$k."</b>:<br />\n"; echo "<pre>\n"; print_r(mysql_fetch_assoc($rresult)); echo "</pre>\n"; echo "<br />\n"; } giving this error: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/meee/public_html/somedir/test.php on line 62 I read about: -mysql_fetch_assoc -mysql_query -SHOW TABLES but do not see why this should be failing. Why isn't $result a ' valid MySQL result resource'?$db_billing=mysqli_connect(localhost,metheuser,mypass,billing); if (mysqli_connect_error()) { die("Can't connect: " . mysqli_connect_error()); }mysqli//$dbname = 'billing'; $sql = "SHOW TABLES";$result = mysql_query($sql); // line 53Now mysql, What are you doing?
if(!$db_selected) {
die("Can't use database: " . mysql_error());
}
if (!$db_billing) { die('Could not connect: ' . mysql_error()); }
$sql = "SHOW TABLES";
$result = mysql_query($sql) or die("query failed: " .mysql_error());
$resulttest = mysql_fetch_assoc($result);
foreach($resulttest as $k => $v) { //line 62
$ssql = "DESCRIBE ".mysql_real_escape_string($v);
$rresult = mysql_query($ssql);
echo "<b>".$k."</b>:<br />\n";
echo "<pre>\n";
print_r(mysql_fetch_assoc($rresult));
echo "</pre>\n";
echo "<br />\n";
}
?>
The only big difference from what you had is that I moved the mysql_fetch_assoc($result); into a separate line rather then running it from the foreach...
Let me know if that helps.