Re: unsetting a referenced parameter in a function

Tom Worster wrote: > though the manual is perfectly clear that this should be expected, i was a > bit surprised that the result of the following is 42 > > <?php > function foo(&$a) { > $a = 42; > unset($a); > $a = 'meaning'; > } > foo($a); > print("$a\n"); > ?> > > normally i would expect unset() to free some memory. but in this example it > doesn't and has a different behavior: it releases foo's reference to the > global $a, allowing the next line to define a local $a. > > i think i'd have preferred compile error. > > Well, you unset the reference and then you assigned 'meaning' to a local function variable $a. Why would you get a compile error? -- Thanks! -Shawn http://www.spidean.com