Re: Making several variables into 1 variable

From: Date: Tue, 28 Jul 2009 15:25:50 +0000
Subject: Re: Making several variables into 1 variable
References: 1 2  Groups: php.general 
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On Tue, Jul 28, 2009 at 10:40 AM, Miller, Terion<tmiller@springfi.gannett.com> wrote: > > > > <,snip> >> > > You can also do this right within MySQL without needing to create a > variable.  This should work: > $sql = "SELECT DISTINCT restaurants.ID, name, address, inDate FROM > restaurants, inspections WHERE restaurants.name != '' AND > datediff(curdate(),inspections.inDate)>=30 GROUP BY restaurants.ID > ORDER BY 'name' "; > > Take care, > Floyd > > > > Ok I have to do the same thing again but with even more variables posted from a form > I have a form where a user can choose a date range currently the form returns 6 variables > (bmonth, bday, byear, emonth, eday, eyear) now I have to take those and get them all formatted > together (well the bmonth, bday, byear together) in the mm/dd/yy format > > Wait can't I..... > $month = $date(m, $bmonth) like that but then I still end up with 3 > > $month, $day, $year.... Does that work like that $date(m/d/y, $month, $day, $year) > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > Use strtotime to convert a text string into a time value that php can then use to figure out a date. $date = date('m/d/y', strtotime("$month/$day/$year"); -- Bastien Cat, the other other white meat

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