Re: ereg_replace to preg_replace translation

m a r k u s wrote: > Hi all, > > I see that from PHP 5.3.0 ereg_replace() function is deprecated and > throws a warning. > I would like to use the preg_replace() function as an alternative of > ereg_replace() function but... can't undestand the "\n#[^\n]*\n" > expression. > > $sql = ereg_replace("\n#[^\n]*\n", "", $sql); > > Any help for tranlation or alternative ? > Thanks > > -- > m a r k u s Here's a good regex tutorial: http://www.regular-expressions.info/ But to answer your question, \n#[^\n]*\n means the match must: start with a newline(\n) followed by a pound sign (#) followed by 0 or more characters (*) that are not a newline(^\n) all the way up to another newline (\n). To translate to preg I think all you need to do is give it delimiters, but that may not be necessary, not sure. "|\n#[^\n]*\n|" -- Thanks! -Shawn http://www.spidean.com