Re: Calendar Problem

At 4:08 PM -0400 8/11/09, Robert Cummings wrote:

tedd wrote:

Hi gang: I want to show the dates for all Fridays +-30 days from a specific date. For example, given today's date (8/11/2009) the Fridays that fall +-30 days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and Sept 4. I'm curious, how would you guys solve this?

<?php $fridays = array(); for( $i = -30; $i <= 30; $i++ ) {

    $mod = $i < 0 ? $i : '+'.$i;

    $time = strtotime( $mod.' day' );

    if( date( 'D', $time ) == 'Fri' )
    {
        $fridays[] = date( 'Y-m-d', $time );
    }

} print_r( $fridays ); ?> Cheers, Rob.

Rob: That's slick -- you never let me down with your simplicity and creativity. My solution was to find the next Friday and then cycle through +-28 days (four weeks) from that date, like so: <?php $fridays = array(); for( $i = 1; $i <= 7; $i++ ) { $time = strtotime( $i . ' day' ); if( date( 'D', $time ) == 'Fri' )

      {
      $start = 28 - $i;
      $end = 28 + $i;
      }

} for( $i = -$start; $i <= $end; $i += 7 ) { $time = strtotime( $i . ' day' ); $fridays[] = date( 'Y-m-d', $time ); } print_r( $fridays ); ?> Your solution had 61 iterations (for loop) while mind had only 21, so mine's a bit faster. Here's the comparison: http://php1.net/b/fridays/ But I'll use your solution -- it's more elegant. Thanks for the code, tedd -- ------- http://sperling.com http://ancientstones.com http://earthstones.com