Re: preg_replace anything that isn't WORD

hack988 hack988 wrote: > Use preg_replace_callback instead! > preg_replace_callback is better performance than preg_replace with /e. > --------------------------------------------------------------------------------- > code > > $str="cats i saw a cat and a dog"; > $str1=preg_replace_callback("/(dog|cat|.)/is","call_replace",$str); > echo $str."<BR/>"; > echo $str1; > function call_replace($match){ > if(in_array($match[0],array('cat','dog'))) > return $match[0]; > else > return ""; > } > > 2009/8/24 tedd <tedd.sperling@gmail.com>: >>> On Sat, Aug 22, 2009 at 12:32 PM, “•ÈýÏÝ“•ÂÔ<danondaniel@gmail.com> > wrote: >>>> Lets assume I have the string "cats i saw a cat and a dog" >>>> i want to strip everything except "cat" and "dog" so the >>>> result will be >>>> "catcatdog", >>>> using preg_replace. >>>> >>>> >>>> I've tried something like /[^(dog|cat)]+/ but no success >>>> >>> > What should I do? >> Lot's of ways to skin this cat/dog. >> >> What's wrong with exploding the string using spaces and then walking the >> array looking for cat and dog while assembling the resultant string? >> >> Cheers, >> >> tedd >> >> >> -- >> ------- >> http://sperling.com >> http://ancientstones.com >> http://earthstones.com >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> >> > Certain posts of mine seem to get sucked into a black hole and I never see theme. Maybe because I use this list as a newsgroup? Anyway, what I posted before: Match everything but only replace the backreference for the words: $s = "cats i saw a cat and a dog"; $r = preg_replace('#.*?(cat|dog).*?#', '\1', $s); -- Thanks! -Shawn http://www.spidean.com