Re: Whacky increment/assignment logic with $foo++ vs ++$foo
| From: | Tommy Pham | Date: | Tue, 06 Oct 2009 18:11:31 +0000 |
| Subject: | Re: Whacky increment/assignment logic with $foo++ vs ++$foo | ||
| References: | 1 2 3 4 5 6 7 8 9 10 11 12 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-298677@lists.php.net to get a copy of this message | ||
----- Original Message ----
> From: tedd <tedd.sperling@gmail.com>
> To: Martin Scotta <martinscotta@gmail.com>; Paul M Foster <paulf@quillandmouse.com>
> Cc: php-general@lists.php.net
> Sent: Tue, October 6, 2009 11:08:14 AM
> Subject: Re: [PHP] Whacky increment/assignment logic with $foo++ vs ++$foo
>
> At 10:48 AM -0300 10/6/09, Martin Scotta wrote:
> > No matter how silly it can looks like (a = a++) it is still completely valid
> > code and it SHOULD run without problems.
>
> Yeah, it's a valid as:
>
> $a = $a;
>
> and does the same thing, which is nothing.
>
> If you want a statement that does something, then use:
>
> $a = ++$a;
>
> or simply:
>
> $a++;
>
> or
>
> ++$a;
>
> Any of those will increment $a, whereas ($a = $a++;) does nothing.
>
> Cheers,
>
> tedd
>
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I find it interesting for a discussion to go on this long for something as
$a = $a++;
which should have never happened in the first place ;)
Regards,
Tommy