RE: [PHP] FILTER_VALIDATE_INT - newbie question

> Well, it was only a guess, but if you look at the integer limit on 32-bit systems, you'll > see that the upper limit > for numbers is 2147483647 (or 2^31-1) which would explain maybe your > upper limit problem. > > Also, I think you're getting confused over the zero with exactly what you are asking PHP > to do. filter_var() returns > true if the filter matches. If the 0 match is returned as a false, > then filter_var() will return false. You're then > inverting that with a !, all of which is > inside an if() statement. Essentially this would mean that if the filter > returns false then the > instructions inside of the if statement are carried out. I always thought that that was a limit of the number of digits an integer value could have, and not the actually int value... I guess I was wrong. :s You are right, I've tested with: 2147483647 it worked. I've tested with: 2147483648 It displays the error. "you're getting confused over the zero with exactly what you are asking PHP to do" Absolutely... :( If I put 0 filter_var() will return false. If I put 0342352 filter_var() will also return false. Could we say that: if it is indeed the fact, that filter_var() returns false when it finds a 0 at the beginning of a given number... "then the instructions inside of the if statement are carried out." And here may be the reason for displaying the error message when we have the 0 leading a number. And my point was exactly here "If the 0 match is returned as a false" Why should filter_var() do something like this? Should the filter_var() interpretate 0 as a number without boolean semantic value? Please be patient... Regards, Márcio