Re: Averages

From: Date: Wed, 13 Dec 2000 16:46:55 +0000
Subject: Re: Averages
References: 1  Groups: php.general 
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On [13 December 2000 11:33] (David Smith), wrote: } I have a number field counting downloads and a date field. I would like to } create a query showing most downloaded files using the average downloads a } day via the date and count fields. } } Example. } } File 1 added 2000-12-11 15:27:22 total downloads = 98 average = 49/day } File 2 added 2000-12-02 15:27:22 total downloads = 25 average = 2/day } File 3 added 2000-12-13 15:27:22 total downloads = 158 average = } 158/day } } Now I would like to use this info and create a query showing this info } placing the most downloads a day on top. In this case: } } File 3, File 1, file 3. } } Any ideas to creating the statement? } } $query = "select * from warbirds_db WHERE FileCount Average of FileDate } ORDER BY FileCount DESC LIMIT 0, 25"; I think you can get it by something like this: SELECT *, FileCount / TO_DAYS((NOW() - added_date)) AS average FROM warbirds_db ORDER BY average DESC - Diogo Zulli ----------------------[ www.sphynx.com.br ]--------------------------- "Why Live on The Edge When You Can BASE Jump Off It"

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