Re: Display just 1 record in a query
| From: | Ashley Sheridan | Date: | Tue, 12 Jan 2010 21:57:41 +0000 |
| Subject: | Re: Display just 1 record in a query | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-301045@lists.php.net to get a copy of this message | ||
On Tue, 2010-01-12 at 13:52 -0800, dealtek@gmail.com wrote:
> I did a query... then I display records like:
>
> <table>
> <?php do { ?>
> <tr>
> <td><?php echo $row_cur['tid']; ?></td>
> <td> </td>
> </tr>
> <?php } while ($row_cur = mysql_fetch_assoc($cur)); ?>
> </table>
>
>
> Q: but how I i just display a particular record with out the do /
> while loop?
>
> like just the 2nd record only:
>
> i tried
> <?php echo $row_cur['tid',2]; ?>
> but this makes an error....
>
> or $row_cur('tid',2) --- hmmm what's the syntax?
>
>
>
> Thanks,
> dealtek@gmail.com
> [db-10]
>
>
Depends on how you're creating running the query. You could do something
like:
echo mysql_result($result, 1, 'fieldname');
Where $result is your result object and 1 is a 0 indexed array, so would
be the second result.
Thanks,
Ash
http://www.ashleysheridan.co.uk