Re: PHP Syntax Help - Check?

Hmm. OK with the help below, I am closer. The other fields on the page are getting passed via form fields that look like this: input type="text" value="<?php echo check('element9'); ?>" name="form[element9]" size="40" maxlength="255" so I added: input type="text" value="<?php echo check('my_id'); ?>" name="form[my_id]" size="40" maxlength="255" and formcheck.php has: <?php //start the session session_start(); //array of fields in form. (In the format "field_name" => "field_label") $form_fields = array( "element0" => 'Your Name:', "element1" => 'Your Email:', "element4" => 'Item Number:', ..... ); and I added: "my_id" => 'My ID Is:', And this works! So when I am on mypage.php and I enter a value into the form field "my_id" it carries over and repopulates should the form fail validation. But upon initial load of the page from my link of mypage.php?my_id=5 (so I am not getting there via a form submit) how do I get the value into the form field? --Rick On Feb 25, 2010, at 1:02 AM, viraj wrote:

if you do the redirection with header('Location: /mypage.php'), setting a variable on formcheck.php is not enough. if you modify the header('Location: /mypage.php') to.. header('Location: /mypage.php?my_id=5') it will take the variable to mypage.php as $_GET['my_id] you can not expect a variable value set in to $_POST array to reflect on a totally different page without making it a form post (aka use of proper headers). i guess, it's time to you to read about session_start() method and the array $_SESSION available in php :) ~viraj On Thu, Feb 25, 2010 at 11:22 AM, Rick Dwyer <rpdwyer@earthlink.net> wrote:

OK... external function... that would explain why I could not locate it. Let me get right to the problem I am having with this code as someone may be able to help directly. I have a link on a page that opens a contact form. The link is mypage.php?my_id=5 So on mypage.php, I capture this value with: $my_id=$_GET['my_id']; I understand this much. But when the end user submits this contact form they do so to formcheck.php and if formcheck.php sees a required field is blank, it throws it back to mypage.php with an alert. BUT, I lose the value of the variable $my_id. SO, I created a hidden field on mypate.php with value="<?php echo $my_id; ?>" and on formcheck.php, I added $my_id = $_Post['my_id']; However, when formcheck.php returns me to mypage.php, $my_id is still blank. Very frustrating. Any help determining what I am doing wrong is greatly appreciated. Thanks. --Rick On Feb 25, 2010, at 12:31 AM, Paul M Foster wrote:

On Thu, Feb 25, 2010 at 12:16:08AM -0500, Robert Cummings wrote:

Rick Dwyer wrote:

Hello all. I'm trying to learn PHP on the fly and I have a line of code that contains syntax I can't find documented anywhere: php echo check('element8'); In the above line, can someone tell me what "check" means?

In the above, check is a function. It is being called with parameter 'element8'.

This is true. But perhaps more importantly, check() is not a native PHP function. Thus it comes from some other library or group of external functions. Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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--~viraj -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php