Re: Math Question....
| From: | Ashley Sheridan | Date: | Thu, 22 Apr 2010 14:13:03 +0000 |
| Subject: | Re: Math Question.... | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-304418@lists.php.net to get a copy of this message | ||
On Thu, 2010-04-22 at 10:17 -0400, Dan Joseph wrote:
> On Thu, Apr 22, 2010 at 10:12 AM, Stephen <stephen-d@rogers.com> wrote:
>
> > 1,252,398 DIV 30 = 41,746 groups of 30.
> >
> > 1,252,398 MOD 30 = 18 items in last group
> >
> Well, the only problem with going that route, is the one group is not
> equally sized to the others. 18 is ok for a group in this instance, but if
> it was a remainder of only 1 or 2, there would be an issue. Which is where
> I come to looking for a the right method to break it equally.
>
How do you mean break it equally? If the number doesn't fit, then you've
got a remainder, and no math is going to change that. How do you want
that remainder distributed?
Thanks,
Ash
http://www.ashleysheridan.co.uk