Re: regular expression

2010/6/1 Peter Lind <peter.e.lind@gmail.com>: > On 1 June 2010 17:33, Ashley Sheridan <ash@ashleysheridan.co.uk> wrote: >> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote: >> >>> $re1 = '/^[a-z]++$/i'; >>> $re2 = '/^[a-z ]++$/i'; >>> >>> >>> >>> -- >>> ----- >>> Richard Quadling >>> "Standing on the shoulders of some very clever giants!" >>> EE : http://www.experts-exchange.com/M_248814.html >>> EE4Free : >>> http://www.experts-exchange.com/becomeAnExpert.jsp >>> Zend Certified Engineer : >>> http://zend.com/zce.php?c=ZEND002498&r=213474731 >>> ZOPA : http://uk.zopa.com/member/RQuadling >>> >> >> >> Why the double ++ in the expressions there? Surely one + would match the >> 1 or more characters that you need and the second one would just be >> surplus? >> > > Equally important: why have three people already done this persons > homework. 5 minutes googling would have answered this ... > Even more important: No answer is correct, because f.e. "äüßćéâ" are also letters. Bye ;-)