Re: What's wrong with this code?

Could the exit() be terminating it? Do you need this exit() as the else for that if statement? Try deleting just the else {}. JAT Karl Sent from losPhone On Jun 5, 2010, at 6:54 PM, David Mehler <dave.mehler@gmail.com> wrote:

Hello, I've got a while loop outputting values from a database. Briefly it looks like this: while($row = mysql_fetch_array($result3)) { echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['type'] . "</td>"; echo "<td>" . $row['startdate'] . "</td>"; if (!empty($row['EndDate'])) { echo "<td>" . $row['enddate'] . "</td>"; } else { exit(); } echo "<td>" . $row['location'] . "</td>"; echo "<td>" . $row['summary'] . "</td>"; echo "<td>" . $row['description'] . "</td>"; echo "</tr>"; } That's not the whole code, but it is the problem code. Some output has the ending date set, one or two records i can't remember how many i entered with one, most do not, i want the echo to be conditional. The output stops right before the if statement, echoes startdate and that's it, comment out the if block and it works fine. Thanks. Dave. --PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php