RE: [PHP] online/offline script help!!

From: Date: Fri, 15 Dec 2000 23:28:14 +0000
Subject: RE: [PHP] online/offline script help!!
References: 1  Groups: php.general 
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place unix timestamp in datetime column do your check $online=time()-$offline; #(assuming that $offline is a number of seconds) $result={db}_exec("select Name from myTable where DATETIME>$online"); you have answered the rest, just drill outthe code and insert the appropriate database tags/fields Dave -----Original Message----- From: Broder B [mailto:broder_b@chello.se] Sent: Friday, December 15, 2000 5:47 PM To: Php General Mailing List Subject: [PHP] online/offline script help!! Yo! I'm working on a script wich will keep track of user online or offline. = When a user logs into a site, the script will register the user with an = unique ID and the time when the user logged in, in a database table. On = further requests from the user on any page of the site a script will = query a database for the users unique id and time. If the ID exists and = it is still valid, the script will update the time column with the = current time. When a user has been inactive (not have had any requests = that have updated the time coumn) the user is seen as offline. My = problem is the time. In the database table the column is of type = DATETIME and I want to know how to figure out if the user is online or = not. The original idea I had is: If table_time is x min older than NOW() = then user =3D offline How can I do this? Answers much appreciated /Broder

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