RE: [PHP] SQL Syntax
| From: | Jan Reiter | Date: | Wed, 16 Jun 2010 01:23:25 +0000 |
| Subject: | RE: [PHP] SQL Syntax | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-306186@lists.php.net to get a copy of this message | ||
Thanks. That was my first attempt, too. Only this will throw out rows, that meet only one of the
conditions, too. For example, I would get all pictures that are bigger than 100, regardless of type,
and all pictures that are of type jpg, no matter the size.
Doing it with a view would be an option, but that would immensely decrease flexibility.
I guess I have to keep on cooking my brain on this ;-)
I think I did it before, a few years ago when MySQL didn't support views yet, but I can't
find that stuff ...
@Dan: Thanks for forwarding my mail to the MySQL List!
Regards,
Jan
From: Ashley Sheridan [mailto:ash@ashleysheridan.co.uk]
Sent: Wednesday, June 16, 2010 3:09 AM
To: Jan Reiter
Cc: php-general@lists.php.net
Subject: Re: [PHP] SQL Syntax
On Wed, 2010-06-16 at 02:58 +0200, Jan Reiter wrote:
Hi folks!
I'm kind of ashamed to ask a question, as I haven't followed this list very
much lately.
This isn't exactly a PHP question, but since mysql is the most popular
database engine used with php, I figured someone here might have an idea.
I have 2 tables. Table A containing 2 fields. A user ID and a picture ID =>
A(uid,pid) and another table B, containing 3 fields. The picture ID, an
attribute ID and a value for that attribute => B(pid,aid,value).
Table B contains several rows for a single PID with various AIDs and values.
Each AID is unique to a PID. (e.g. AID = 1 always holding the value for the
image size and AID = 3 always holding a value for the image type)
The goal is now to join table A on table B using pid, and selecting the rows
based on MULTIPLE attributes.
So the result should only contain rows for images, that relate to an
attribute ID = 1 (size) that is bigger than 100 AND!!!!!!! an attribute ID =
5 that equals 'jpg'.
I know that there is an easy solution to this, doing it in one query and I
have the feeling, that I can almost touch it with my fingertips in my mind,
but I can't go that final step, if you know what I mean. AND THAT DRIVES ME
CRAZY!!!!!!
I appreciate your thoughts on this.
Regards,
Jan
You'll be looking for something like this (untested):
SELECT * FROM a
LEFT JOIN b ON (a.pid = b.pid)
WHERE (b.aid = 1 AND b.value > 100) OR (b.aid = 3 AND b.value = 'jpg')
Obviously instead of the * you may have to change to a list of field names to avoid fieldname
collision on the two tables.
Thanks,
Ash
http://www.ashleysheridan.co.uk