Re: Array help.

On Fri, Jul 30, 2010 at 3:44 PM, Joshua Kehn <josh.kehn@gmail.com> wrote: > > On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote: > >> I have a query that may not always return a result for a value, I need >> to reflect this with a "0". I am trying to overcome this by doing this >> (the keys are ID's): >> >> while ($row = mysql_fetch_row($statusQuery)) { >> >>        $cat = >> array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0); >> >>        switch ($row[1]) { >>            case 0: $cat[0] = $row[0]; break; >>            case 1: $cat[1] = $row[0]; break; >>            case 11: $cat[11] = $row[0]; break; >>            case 12: $cat[12] = $row[0]; break; >>            case 13: $cat[13] = $row[0]; break; >>            case 14: $cat[14] = $row[0]; break; >>            case 15: $cat[15] = $row[0]; break; >>            case 16: $cat[16] = $row[0]; break; >>            case 17: $cat[17] = $row[0]; break; >>            case 19: $cat[19] = $row[0]; break; >>        } >> >>        print_r($cat); >>    } >> >> Which gives me this: >> >> Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 >> [15] => 0 [16] => 0 [17] => 0 [19] => 0 ) >> Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]s >> => 30 [16] => 0 [17] => 0 [19] => 0 ) >> >> The query only return 2 rows: >> >> 15 | 30 >> 0 | 15547 >> >> What am I doing wrong? Is there a more elegant way to achieve what I want? >> >> Thanks. >> >> -- >> Paul Halliday >> Ideation | Individualization | Learner | Achiever | Analytical >> http://www.pintumbler.org >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php >> > > Paul- > > Why not say: > > $cat = array(); > if(isset($row[1]) > { >    $cat[$row[1]] = $row[0]; > } > > print_r($cat); > > Regards, > > -Josh I need the results that don't have values assigned though. ex: c = 0 h = 9 t = 0 f = 21 Even if the query returned only: h = 9 f = 21