Re: regexp problem

Joe Stump wrote: > > If all you want to do is replace a word with another use str_replace() - it's > quite a bit faster and just the same thing. > > $new_string = str_replace('the','foo',$old_string); > > --Joe > > On Sun, Dec 17, 2000 at 01:56:55AM +0000, Chris Jones wrote: > > Hi > > > > I'm working on simple regexp that works fine with sed, but doesn't seem > > to work with PHP 4.0.3pl1. > > > > For example, I want to replace all occurances of the word "the" with > > "foo", so I use: > > > > cat file.txt | sed -e "s/\Wthe\W/ foo /g" > > > > and it works. Translating this into php would be: > > > > print (egrep_replace ("\Wthe\W", " foo ", $text)); > > > > but this just produces the original $text with nothing changed. What am I > > doing wrong? > > Chris Jones wrote: > > Hi > > In article <20001216175823.B21270@zorka.com>, "Joe Stump" > <joe@earth.care2.com> wrote: > > > it's quite a bit faster and just the same thing. > > It's not "just the same thing", the regexp "\Wfoo\W" only replaces > "foo" > where it's a whole word, str_replace(); would replace "foobar", which I > don't want. > Thanks for the suggestion anyway - fortunately I managed to fix the > problem, I think I must have had a typo or something. > Hello Perhaps this would do what you want: <? $text = "foo, the foobar and barfoo are -foo- while foo is not foo"; print "$text\n"; print( ereg_replace('([^[:alnum:]]|^)foo([^[:alnum:]]|$)', '[\\1]FOO[\\2]', $text) ) . "\n"; ?> On my PHP 3.0.7 the output is (are?) : foo, the foobar and barfoo are -foo- while foo is not foo []FOO[,] the foobar and barfoo are [-]FOO[-] while[ ]FOO[ ]is not[ ]FOO[] Tell us if you found a better code :-) Regards, xinchro __________________________________________________ Do You Yahoo!? Yahoo! Shopping - Thousands of Stores. Millions of Products. http://shopping.yahoo.com/