Re: Reg Expression

Hi Scott: > Hi guys I have some html text and I am trying to find all instances of '<a > href="*">' and replace it with [link | *] > ... > I can put it back into > '<a href="*">'. * will could contain a-z, A-Z, 0-9 and/or #. That's not accurate. URL's can contain a wide variety of characters. Here's some code I use to turn URL's into hyperlinks: eregi_replace("(http://|https://|ftp://|gopher://|news:|mailto:) ([[:alnum:]/!#$%&'()*+,.:;=?@~-]+)([[:alnum:]/!#$%&'()*+:;=?@~-])", "<a href=\"\\1\\2\\3\">\\1\\2\\3</a>", "$Val"); Performs the following, for example: http://foo.org <a href="http://foo.org">foo.org</a> > $content = ereg_replace("<\/a href=\"(.+)\">", "[link]", > $content); You'll get tripped up by that expression because the atom "(.+)" will grab everything up to the last ">" in the string. So, if you have several links in the string, you'll cram all the text between the first "<a href" to the last ">" into one link. Not what you're looking for. So, use "([[:alnum:]/!#$%&'()*+,.:;=?@~-]+)" for it instead. Also, use eregi to ensure the thing works if someone has text in upper case. Uh, why do you have "<\/a href" rather than "<a href" ??? Anyway, here's a quick, untested stab at what you want: $content = eregi_replace("(<a href=\") ([[:alnum:]/!#$%&'()*+,.:;=?@~-]+)(\">)", "[link | \\2]", "$content"); Good luck, --Dan -- PHP scripts that make your job easier http://www.analysisandsolutions.com/code/ SQL Solution | Layout Solution | Form Solution T H E A N A L Y S I S A N D S O L U T I O N S C O M P A N Y 4015 7 Ave, Brooklyn NY 11232 v: 718-854-0335 f: 718-854-0409