Re: Re: Simplest way of enforcing an array of instances of a specific class but treating the whole thing as an array.
| From: | Richard Quadling | Date: | Fri, 25 Feb 2011 09:23:03 +0000 |
| Subject: | Re: Re: Simplest way of enforcing an array of instances of a specific class but treating the whole thing as an array. | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-311576@lists.php.net to get a copy of this message | ||
On 24 February 2011 18:28, David Harkness <david.h@highgearmedia.com> wrote:
> If each array will contain a single type of object, but you need many of
> these arrays, each containing a different type of object, I recommend
> creating a generic "instances-of-class" array using ArrayObject. You can
> enforce the type in append(), offsetSet(), and exchangeArray() and then
> check the configured type in methods that want to enforce it.
> function drawMap(TypedArray $latLngs=null) {
> if ($latLngs && !$latLngs.containsOnly('LatLng')) {
> throw new InvalidArgumentException('$latLngs must contain only
> LatLngs');
> }
> ...
> }
> I guess since there are only three methods to override it wouldn't be too
> painful to create a separate class for each type to get method declaration
> type hinting. If you aren't containing too many classes and you pass them
> around a lot, it may be worth it since you won't have to test the container
> inside the method at all.
> function drawMap(LatLngArray $latLngs=null) ...
> Looks like someone beat us to it:
>
> http://liamgraham.wordpress.com/2007/05/21/typesafe-arrays-for-php/
> David
>
That's it and in the direction I was heading.
Thanks David - and liamgraham
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY