Re: mysql_num_rows()
| From: | tedd | Date: | Fri, 25 Feb 2011 23:58:24 +0000 |
| Subject: | Re: mysql_num_rows() | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-311581@lists.php.net to get a copy of this message | ||
At 12:40 AM -0500 2/22/11, Gary wrote:
Can someone tell me why this is not working? I do not get an error message, the results are called and echo'd to screen, the count does not work, I get a 0 for a result... $result = mysql_query("SELECT * FROMGary: With regard of the count thing, why not let MySQL do the work? $query = "SELECT COUNT(*) AS total FROM 'counties' WHERE name = 'checked' "; $result = mysql_query($query) or die(mysql_error()); $total = $rowcount['total']; Cheers, tedd -- ------- http://sperling.com/countiesWHERE name = 'checked'") or die(mysql_error()); if ( isset($_POST['submit']) ) { for($i=1; $i<=$_POST['counties']; $i++) { if ( isset($_POST["county$i"] ) ) { echo "You have chosen ". $_POST["county$i"]." <br/>";} }} $county_total=mysql_num_rows($result); while($row = mysql_fetch_array($result)) {$i++;echo $row['name'];} $county_total=mysql_num_rows($result); echo "$county_total"; echo 'You Have ' . "$county_total" . ' Counties '; ?>