Re: Handling exit in eval

2011/3/14 Thomas Björk <tb@bytecode.se>: > Is there any way to emulate an exit in eval without exiting the calling > script. > > <?php > $s = 'echo "Shows"; exit; echo "Doesn\'t show"; '; > eval($s); > echo "Never comes here"; > ?> > > > I would like to do something like this: > <?php > $s = 'echo "Shows"; exit; echo "Doesn\'t show"; '; > > function MakeItStop() { >  // Do something to make the eval stop >  // without halting the script > } > > $s = str_replace('exit;', 'MakeItStop();', $s); > > eval($s); > echo "Never comes here"; > ?> > > > A simple return would fix it IF the return isn't located within a > function. > > > Any good suggestions? > > Thanks in advanced > Thomas Björk > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > Can you provide a more realistic example? Just don't code anything after the last line of code that contains the exit? Surely. http://uk.php.net/manual/en/function.eval.php does say that ... "A return statement will immediately terminate the evaluation of the string ." So, there's your answer I suppose. Replace "exit" with "return". -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY