Re: str_replace

On 24 April 2011 16:44, Ron Piggott <ron.piggott@actsministries.org> wrote: > > I am trying to figure out a syntax that will replace each instance of % with > a different letter chosen randomly from the string $puzzle_filler. > $puzzle_filler is populated with the letters of the alphabet, roughly in the > same ratio as they are used. > > This syntax replaces each instance of % with the same letter: > > $puzzle[$i] = str_replace ( "%" , ( substr ( $puzzle_filler , rand(1,98) , 1 > ) ) , $puzzle[$i] ); > > Turning this: > > %ECARBME%TIPLUP%%%%%%%E%% > > Into: > > uECARBMEuTIPLUPuuuuuuuEuu > > Is there a way to tweak my str_replace so it will only do 1 % at a time, so > a different replacement letter is selected? > > This is the syntax specific to choosing a replacement letter at random: > > substr ( $puzzle_filler , rand(1,98) , 1 ); > > Thanks for your help. > > Ron > > The Verse of the Day > “Encouragement from God’s Word” > http://www.TheVerseOfTheDay.info > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > Something like this ... <?php $s_Text = '%ECARBME%TIPLUP%%%%%%%E%%'; $s_PuzzleFilter = '0123456789'; echo preg_replace_callback( '%', function() use($s_PuzzleFilter) { return substr($s_PuzzleFilter, mt_rand(0, strlen($s_PuzzleFilter) - 1), 1);}, $s_Text ); -- Richard Quadling Twitter : EE : Zend @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY