Re: postgresql database access failure
| From: | Daniel Brown | Date: | Sat, 30 Apr 2011 16:23:43 +0000 |
| Subject: | Re: postgresql database access failure | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-312593@lists.php.net to get a copy of this message | ||
Readers? Sounds like you spend too much time writing newsletters
(to the wrong address, since php-general-digest-help@lists.php.net is
a self-help command list for digest-form subscriptions). ;-P
On Sat, Apr 30, 2011 at 04:41, e-letter <inpost@gmail.com> wrote:
> <?php
> $db = pg_connect('dbname=databasename user=username');
> $query = 'SELECT * FROM databasename';
> $value=pg_fetch_result($query,1,0);
> echo 'export of database is ',$value,'';
> ?>
> <p>
> why does this fail?
How is it failing? What error(s) are you seeing on screen or in
your log files? Noting that $value would contain an array, is that
the problem? And why are you using ending quotes in your echo? You
should just place the semicolon immediately after $value.
> </p>
> </body>
> </html>
>
> The following php code produces the user agent:
>
> <?php
> echo '$_SERVER['HTTP_USER_AGENT']';
> ?>
First of all, no it doesn't. Placed inside single quotes, it'll
not only try to return it verbatim (i.e. - the variable would be
printed to screen), but it'll also cause a parse error, as you reuse
single quotes in the variable key container.
--
</Daniel P. Brown>
Network Infrastructure Manager
http://www.php.net/