Re: It works but HUH!

On Wed, 20 Dec 2000, Sefton wrote: > Hello Everybody, > > This sort of works. > A. It returns all the values > B. it only writes the first row into a table the rest is all over the place > C. The images that are there still just load the 1.gif image. > > What could I be doing wrong? > Yes I am a dumb ass and cannot work it out, even with this part coming from > a question i have already asked. > Please HELP! > > It is supposed to return the information from a MySql Database. If the photo > of the vehicle is there then it is display in the first cell of that row, > but if the photo is not there it displays the 1.gif image. > <? > // My first lot of code goes here, I haven't displayed it. It is the problem > > while ($myrow = mysql_fetch_row($result)) { > > echo "<tr><td>$myrow[0]</td><td width=130>"; > if (file_exists("/si/$myrow[0].gif")) { > echo "<img src=\"si/$myrow[0].gif\">"; > } > else { > echo "<img src=\"si/1.gif\"></td>"; > > echo > "<td>$myrow[1]</td><td>$myrow[2]</td><td>$myrow[3]</td>"; > echo > "<td>$myrow[4]</td><td>$myrow[6]</td><td>$$myrow[9]</td></tr>\n"; > $myrow[0]; > echo "</table>\n"; > } > } > ?> > Try putting the arrays in quotes in braces: "/si/{$myrow[0]}.gif" "<td>{$myrow[1]}</td>..." -- Ignacio Vazquez-Abrams <ignacio@openservices.net>