Re: RE: RE: [PHP] Use of preg_replace

On 24 Jul 2011 at 19:57, Dajka Tamás <viper@vipernet.hu> wrote: > You want to do it in a greater text, I think. See below. > 1,$s/^>(>*From )/\1/ > > $line = preg_replace ($pattern, $replacement, $line); > > Adding one '>': > > preg_replace('/(^[>]+From )/','>$1', $line) > > Removing one '>': > > preg_replace('/(^>([>]+From )/','$1', $line) ^ | Missing ) -------------------+ In fact I forgot to mention that the string always starts at the start of the line. So, I experimented a bit and the following works: $onemore = preg_replace ('/^(>*From )/', '>$1', $line); $oneless = preg_replace ('/^>(>*From )/', '$1', $line); Thanks for the help. -- Cheers -- Tim