Re: form validation

From: Date: Fri, 12 Aug 2011 15:53:06 +0000
Subject: Re: form validation
References: 1  Groups: php.general 
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On 12 August 2011 16:42, Chris Stinemetz <chrisstinemetz@gmail.com> wrote: > I have a select menu created by a foreach loop. I am trying to > validate that there was a selection made before it is submitted to the > database. But I am not doing something correctly. > > <select name="market" class="ajax" > onchange="javascript:get(this.parentNode);"> > <option value="">Choose...</option> > <?php >    foreach($market_prefix as $key => $value) >        { >        $selected = ''; >        if($value == $market) >        { >        $selected = 'selected'; >        } >        echo '<option value="', htmlspecialchars($value), '" > ', $selected, > '>', htmlspecialchars($market_name[$key]), '</option>'; >        } >        ?> > </select> > > I am using the folling on the posted page. > > if (! array_key_exists($_POST['market'], $market_name)) > { >    echo "You did not select a market."; > } > > Thank you, > > Chris $_POST['market'] won't exist if you haven't chosen one. Turn on your error reporting and you should see something appropriate. At a bare minimum, adding ... isset($_POST['market']) as the first thing to test (before seeing if the value is in $market_name (though I would have thought $market_names would have been a better name for the variable - implies more than 1 market). -- Richard Quadling Twitter : EE : Zend : PHPDoc @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea

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