Re: phpbuilder article question

File local isn't a directory - it's a file named local with no .php on the end. What the article neglects to mention is if you use foo.php/2/3 it will still parse out just fine. --Joe On Fri, Dec 22, 2000 at 12:41:22AM -0800, Gerry Chu wrote: > The phpbuilder article "Building Dynamic Web Pages with Search Engines in > Mind" has this example: > > ---------- > <Location /local> > ForceType application/x-httpd-php3 > </Location> > > This forces every request that starts with "/local/" to call a script called > "local" (just "local", not "local.php3") in the $DOCUMENT_ROOT > (usually > called "/htdocs/") of your server. "local" then uses PHP to parse the URL > and act accordingly. The code for my "local" script is on the last page of > this article. You can of course replace "local" with any filename you want, > as long as you change your httpd.conf accordingly. > ----------- > > So what it's saying is that when a user accesses a page with a $PHP_SELF > that starts with /local, it calls a script called "local" in $DOCUMENT_ROOT. > So the "local" dir also must be in $DOCUMENT_ROOT. Wait...you can't have a > file and a directory with the same in name in the same directory, can you? > > How'd they do it? > > Thanks, > > Gerry > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net --- Joe Stump PHP Programmer www.Care2.com