Re: Have little enough hair as it is ...

2012/3/12 Lester Caine <lester@lsces.co.uk>: > More irritating is > 'Notice: Array to string conversion' which are coming up all over the place. > I can understand what the problem is ... but trying to remove the notices is > more challenging ... > > $secondsGap[] = array($gap[0] * 60, $gap[1] * 60); > if( isset($secondsGap[1]) ) { >        $gapName = $secondsGap[0]."to".$secondsGap[1]; > } else { >        $gapName = $secondsGap[0]; > } > $secondsGap[] is two numbers, which are used to create the name string, so > what is the 'official' way of making this work without generating warnings? > Hi, Lester I suggest that all done with this variable before is not of interest ... Assuming this, I'd say the following: > $secondsGap[] = array($gap[0] * 60, $gap[1] * 60); Implicit initializing of an array that has the following structure: array( array(int, int) ); > if( isset($secondsGap[1]) ) { Trying to get the second element .. which will never happen if you haven't added an element before the snipped you pasted here. > $gapName = $secondsGap[0]."to".$secondsGap[1]; > } else { > $gapName = $secondsGap[0]; > } [some-code] I'm quite unsure what you want to do here. If you'd update the first line as following it would always trigger the first condition: $secondsGap = array($gap[0] * 60, $gap[1] * 60); Bye Simon