RE: [PHP] NULL Problem

Matijn - it worked! Geez... Strange - I don't need the ->value if it actually has a value, only if it's NULL... But it works! Thanks! -----Original Message----- From: Matijn Woudt [mailto:tijnema@gmail.com] Sent: Tuesday, April 24, 2012 1:40 PM To: David Stoltz Cc: php-general@lists.php.net Subject: Re: [PHP] NULL Problem On Tue, Apr 24, 2012 at 7:29 PM, David Stoltz <Dstoltz@shh.org> wrote: > Here's my code (using MSSQL): > > $conn = new COM ("ADODB.Connection")or die("Cannot start ADO"); > $conn->open($connStr); > $query = "SELECT * FROM TABLE WHERE id = ".$id; > $rs = $conn->execute($query); > > This code works fine, and I retrieve the values like this: > > $tmp1 = $rs->fields("column1"); > $tmp2 = $rs->fields("column2"); > Etc... > > > Here's the problem - I'm trying to get a date column that I know is > NULL, but I can't seem to get my code right: > > $tmp = $rs->fields("followup_on"); > if(is_null($tmp)){ >        $followup = ""; > }else{ >        $followup = $rs->fields("followup_on"); > } > > //this results in: Catchable fatal error: Object of class variant could > not be converted to string > //When I try to ECHO the $followup results (and I know the database > value is NULL) > > > So confused - any advice? > It's been a long time ago I worked with ADO (Thank god), but shouldn't you echo $followup->value instead of $followup? If that's not working, try a var_dump($followup), so you can check exactly what it is. - Matijn