Re: why is (intval('444-44444') == '444-44444') EQUAL??!

Using == will compare the two values after type juggling is performed. === will compare based on value and type (identical). PHP Will type juggle the string to an integer. Your if/else is just like saying: php> if (444 == "444") echo 'equal'; else echo 'not equal'; equal -- Mike Mackintosh PHP 5.3 ZCE On Thursday, June 21, 2012 at 10:27 PM, Daevid Vincent wrote: > Huh? Why is this equal??! > > php > $id = '444-44444'; > > php > var_dump($id, intval($id)); > string(9) "444-44444" > int(444) > > php > if (intval($id) == $id) echo 'equal'; else echo 'not equal'; > equal > > or in other words: > > php > if (intval('444-44444') == '444-44444') echo 'equal'; else > echo 'not equal'; > equal > > I would expect PHP to be evaluating string "444-44444" against integer "444" > (or string either way) > > however, just for giggles, using === works... > > php > if ($id === intval($id)) echo 'equal'; else echo 'not equal'; > not equal > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >