Re: arrays in function definition possible?
| From: | Kyle Jerviss | Date: | Wed, 27 Dec 2000 07:33:40 +0000 |
| Subject: | Re: arrays in function definition possible? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-31932@lists.php.net to get a copy of this message | ||
try this:
function useArray($foo=array(0=>3,1=>4))
{
}
you'd need to call it with:
useArray(array(0=>3,1=>4)); or useArray(array(3,4));
Jenny Koozer wrote:
>
> Why won't this work?
>
> function useArray($foo[0]=3,$foo[1]=4)
> {
>
> }
>
> I get a parse error : expecting `')''
>
> Can array info be passed into a function definition
> like this? I am able to call the function like this
> okay :
>
> useArray($foo[0]=3,$foo[1]=4);
>
> But defining defaults this way seems impossible. This
> is strange to me, please explain! My "workaround" is
> to define $foo array and make $foo global but ...
>
> TIA!
>
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