Re: Re: new FTP function

On Fri, Jan 18, 2013 at 9:43 AM, Daniel Brown <danbrown@php.net> wrote: > On Fri, Jan 18, 2013 at 10:33 AM, KISE <wowkise@gmail.com> wrote: >> Paul Dragoonis, >> >> Actually it wont work i did tried it before, if the dir end with / it will >> list the directories inside the path you gave it and if it doesn't have any >> directories it will return false since there is no directories to return. >> >> you have to take out the last / and then remove the directory in question >> and list the files in the parent directory and check if the dir exists >> otherwise it will return false, i spent 3hrs yesterday thinking why its >> returning false even though the directory exists. > > The discussion is now getting more into the general coding realm > than internals, so let's move it over there in case anyone wants to > mention something like: > > function ftp_dir_exists($conn, $currentDir) { > $currentDir = (substr($currentDir,-1,1) == '/') ? > substr($currentDir,0,-1) : $currentDir; > $list = ftp_nlist($conn, '-dF '. $currentDir); > return in_array($currentDir, $list); > } Haven't played with ftp functions at all, but wondering what if you gave it dirname($currentDir) instead of $currentDir? (Still have to do the trailing '/'-ectomy) $list = ftp_nlist($conn, dirname($currentDir)); untested, just a thought.