Re: sessions working? not working?
| From: | Tedd Sperling | Date: | Mon, 12 Aug 2013 14:15:06 +0000 |
| Subject: | Re: sessions working? not working? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-321841@lists.php.net to get a copy of this message | ||
On Aug 12, 2013, at 4:27 AM, Clifford Shuker <clifford.shuker@ntlworld.com> wrote:
> Hi have the following (below) session code at the top of each page.. The
> 'print_r' (development feature only) confirms that on one particular page I
> do log out as the session var = (). but, on testing that page via the URL I
> still get to see the page and all its contents - session var() -.. the page
> has the following 'session_start, DOCTYPE Info then <html><head>containing
> meta info & title</head><body>containing
> style/tables/content/</body></html>
> // end of page. I have copied the same page without the html content (i.e.
> a blank page) and I get to fully log out.. when this page is tested in the
> URL my warning comes up 'you need to login to see this page' which is what I
> want but, I've tried numerous avenues to reconcile my problem to no avail..
> I'm a novice so any help would be appreciated..
>
>
>
> <?php
>
> session_start();
>
> error_reporting (E_ALL ^ E_NOTICE);
>
> $userid = $_SESSION['userid'];
>
> $username = $_SESSION['username'];
>
> print_r($_SESSION);
>
> ?>
>
Ok, but when are you populating the SESSION's? Such as:
$_SESSION['userid'] = $userid;
Also, have a look at this:
http://sperling.com/php/authorization/log-on.php
It might help.
tedd
_______________
tedd sperling
tedd.sperling@gmail.com