Re: Resolving a PHP Notice Error
| From: | Sebastian Krebs | Date: | Tue, 17 Sep 2013 19:42:27 +0000 |
| Subject: | Re: Resolving a PHP Notice Error | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-322077@lists.php.net to get a copy of this message | ||
2013/9/17 Ron Piggott <ron.piggott@actsministries.org>
>
> I am wanting to establish a default sort by preference when the user
> hasn’t specified one. I setup to test this with:
>
> <?php
>
> if ( !is_set( $sort_by_preference ) ) {
>
> $sort_by_preference = "government_wording";
>
> }
>
> ?>
>
> But I am receiving a Notice error:
>
> Notice: Undefined variable: sort_by_preference in GIFI_codes.php on line
> 11- Line 11 is “if ( !is_set( $sort_by_preference ) ) {“What is the correct
> way to test this without triggering a Notice error?Ron
> Ron Piggott
>
Because actually you are looking for isset() (not is_set()).
>
>
>
> www.TheVerseOfTheDay.info
>
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