Re: Date sequence calculating

On Tue, Nov 12, 2013 at 1:25 PM, Ron Piggott <ron.piggott@actsministries.org > wrote: > I am trying to calculate a date sequence using $i in conjunction with “ > (so the represented # is “seen” by PHP) > > The code (below) results in 2 errors: > > Notice: Undefined variable: i_days_ago in /vhosts/ > mypainmanagementtracker.net/public/test.php on line 9 > Notice: Undefined variable: i_days_ago in /vhosts/ > mypainmanagementtracker.net/public/test.php on line 13 > > <?php > > $users_current_date = date('Y-m-d'); > $i = 2; > while ( $i <= 10 ) { > > $dt = new \DateTime( date('Y-m-d H:i:s' , strtotime( > $users_current_date ) ) ); > $dt->modify("-$i days"); > $users_dates["$i_days_ago"]['starting_date'] = > $dt->format('Y-m-d > 00:00:00'); > > $dt = new \DateTime( date('Y-m-d H:i:s' , strtotime( > $users_current_date ) ) ); > $dt->modify("-$i days"); > $users_dates["$i_days_ago"]['ending_date'] = > $dt->format('Y-m-d > 23:59:59'); > > ++$i; > } > ?> > > Is there a way to do this without creating these errors and also “NOTICE” > errors? The dates being calculated will be used in a database query (used > to generate a report based on the activity between the starting and ending > dates). > > Ron > > > Ron Piggott > > > www.TheVerseOfTheDay.info > You need to concatenate the string. Right now php thinks that $i_days_ago is a string since you have it in double quotes. You should do $users_dates[$i . "_days_ago"]['starting_date'] = $dt->format('Y-m-d 00:00:00'); $users_dates[$i . "_days_ago"]["ending_date"] = $dt->format('Y-m-d 23:59:59');