Re: Grabbing IP address information

hi, the response is in json format,you can call json_decode to convert the response string to a php object,ie $ip_obj = json_decode($location); echo $ip_obj->ip . $ip_obj->country_name; ---------- george On Tue, Jan 14, 2014 at 8:54 AM, Jennifer <jennifer@superiorshelving.com>wrote: > Hi everyone! > > My name's Jenni and I'm new to the list. I hope this question > isn't too simple. > > I want to grab some information about an IP address and present it > in a readable fashion, so I wrote the following: > > $location = > file_get_contents('http://freegeoip.net/json/78.18.200.182'); > $location = str_replace('{', '', $location); > $location = str_replace('}', '', $location); > $location = str_replace('"', '', $location); > $location = str_replace(',', "\n", $location); > echo $location; > > However, this seems longer than it needs to be. Is there a better > way to do this? > > Thank you, > Jenni > > Superior Shelving Systems::::.... > http://www.SuperiorShelving.com > > The (Storage|Office|Display) Shelving Specialists > Since 1984 > > Computer Workstations: > > http://www.superiorshelving.com/mfg/nexel/pages/lan-workstations-nexel.php > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >