Re: PHP output fails from AJAX call

On 30 Jan 2014 at 06:27, Adarsh Sharma <eddy.adarsh@gmail.com> wrote: > Hi, > > I am using AJAX and php for creating a small UI that retrieves data from > mysql upon clicking on one button. But i clicked on that , nothing is > happening. Below is my index.html : > > *-- index.html * > > <html> > <head> Missing <script ... > as Niklaus has pointed out. > function week_report_fun(){ > var ajaxRequest; > --- > --- > -- > ajaxRequest.open("GET","ajaxex.php?q="+users,true); What is "users"? Where is your code to get the selected value from the form? > ajaxRequest.send(); > } > > </script></head><body> > <form> > User : <select id="users" onchange="week_report_fun()"> > <option value="">Select a user</option> > <option value="133">av</option> > <option value="168">ad</option> > <option value="78">so</option> > <option value="239">ak</option> > </select></form><br> > <div id="txtHint"><b>Person info will be listed > here.</b></div> > </body></html> Where is your code to get the returned results from your PHP script and display it? -- Cheers -- Tim